擅长:python、mysql、java
<p>您可以使用<code>zip</code>内置函数。它将返回您传递的所有iterables的<code>i-th item</code>。见<a href="https://docs.python.org/3/library/functions.html?highlight=all#zip" rel="nofollow noreferrer">zip doc</a></p>
<p>就你而言:</p>
<pre><code>for it in zip(l1, l2):
# the * is for extracting the items from it
# sep="" does not print any spaces between
# end="" does avoid printing a new line at the end
print(*it, sep="", end="")
</code></pre>