如何停止循环中的操作？

Question

我试图创建一个脚本，自动打开我的在线课程。我写了这段代码：

import webbrowser
import datetime
import time

now = time.strftime("%D, %H:%M")

lesson1 = "03/09/21, 15:38"
lesson2 = "03/10/21, 15:39"
lesson3 = "03/10/21, 15:40"

while True:
    while now != lesson1 and now != lesson2 and now != lesson3:
        print ("Waiting, the current time is " + now)
        now = time.strftime("%D, %H:%M")
        time.sleep(1)

    if now == lesson1:
        print ("LESSON IS OPENING :D")
        webbrowser.open("https://google.com")

    if now == lesson2:
        print ("LESSON IS OPENING :D")
        webbrowser.open("https://google.com")

    if now == lesson3:
        print ("LESSON IS OPENING :D")
        webbrowser.open("https://google.com")

现在，问题是第一个if语句被无限执行，我想让它只执行一次，而不是等到现在==lesson2，然后执行第二个if等等

Answer 1

问题是在每次迭代中，您都要检查当前时间是否等于课程时间，这会导致程序多次打开浏览器。由于您使用的是hours/minutes，因此在当前课程开始后让程序睡眠1分钟会阻止它

样本输入：

import webbrowser
import datetime
import time

now = time.strftime("%D, %H:%M")
print("Current Time   ", now)

lesson1 = "03/10/21, 11:14"
lesson2 = "03/10/21, 11:15"
lesson3 = "03/10/21, 11:16"


while True:
    while now != lesson1 and now != lesson2 and now != lesson3:
        print ("Waiting, the current time is " + now)
        now = time.strftime("%D, %H:%M")
        time.sleep(1)
        
    if now == lesson1:
        print("Opening Google")
        webbrowser.open("https://google.com")
        time.sleep(60)
        now = time.strftime("%D, %H:%M")

    if now == lesson2:
        print("Opening Youtube")
        webbrowser.open("https://youtube.com")
        time.sleep(60)
        now = time.strftime("%D, %H:%M")

    if now == lesson3:
        print("Opening Facebook")
        webbrowser.open("https://facebook.com")
        time.sleep(60)
        now = time.strftime("%D, %H:%M")

---

样本输出：

Current Time   03/10/21, 11:13
Waiting, the current time is 03/10/21, 11:13
Opening Google
Opening Youtube
Opening Facebook

Answer 2

您似乎希望将代码安排在特定时间运行。我建议使用APScheduler库。非常容易使用，而且效率很高