将Prettytable的输出发送到电报

Question

我有以下代码：

从prettytable导入prettytable

myTable = PrettyTable(["Student Name", "Class", "Section", "Percentage"])
  
# Add rows
myTable.add_row(["Leanord", "X", "B", "91.2 %"])
myTable.add_row(["Penny", "X", "C", "63.5 %"])
myTable.add_row(["Howard", "X", "A", "90.23 %"])
myTable.add_row(["Bernadette", "X", "D", "92.7 %"])
myTable.add_row(["Sheldon", "X", "A", "98.2 %"])
myTable.add_row(["Raj", "X", "B", "88.1 %"])
myTable.add_row(["Amy", "X", "B", "95.0 %"])

这将生成一个如下所示的表：

+--------------+-------+---------+------------+
| Student Name | Class | Section | Percentage |
+--------------+-------+---------+------------+
|   Leanord    |   X   |    B    |   91.2 %   |
|    Penny     |   X   |    C    |   63.5 %   |
|    Howard    |   X   |    A    |  90.23 %   |
|  Bernadette  |   X   |    D    |   92.7 %   |
|   Sheldon    |   X   |    A    |   98.2 %   |
|     Raj      |   X   |    B    |   88.1 %   |
|     Amy      |   X   |    B    |   95.0 %   |
+--------------+-------+---------+------------+

我想准确地发送这个表格，而不改变电报信息的格式。因此，我将其写入一个文本文件：

table_txt = table.get_string()
with open('output.txt','w') as file:
    file.write(table_txt)

接下来，我使用以下代码：

import telegram

def send_msg(text):
    token = "******************:***********"
    chat_id = "********"
    bot = telegram.Bot(token=token)
    for i in text:
        bot.sendMessage(chat_id=chat_id, text=i)
new_list = []
with open("output.txt", 'r', encoding="utf-8") as file:
     new_list = file.read()
for i in new_list:
     send_msg()

它的作用是一次发送1个字符的文件内容，直到收到电报错误：

RetryAfter: Flood control exceeded. Retry in 43.0 seconds

请告知我如何解决此问题

Answer 1

问题在于这段代码：

for i in text:
    bot.sendMessage(chat_id=chat_id, text=i)

您没有发送文本，而是对文本进行迭代。通过执行此操作，可以获得整个字符串的子字符串，每个子字符串仅包含一个字符：

text = "hello"
outputs = []
for i in text:
    outputs.append(i)
assert outputs == ['h', 'e', 'l', 'l', 'o']

for i in text:
    print(i)
# h
# e
# l
# l
# o

要解决此问题，您只需发送整个字符串即可：

bot.sendMessage(chat_id=chat_id, text=text)

Answer 2

我不是python开发人员，但我认为这会起作用

import telegram

def send_msg(text):
    token = "******************:***********"
    chat_id = "********"
    bot = telegram.Bot(token=token)
        bot.sendMessage(chat_id=chat_id, text=text)

with open("output.txt", 'r', encoding="utf-8") as file:
     send_msg(file.read())