无法获取Subprocess.Popen以运行参数，但批处理将

Question

java -jar "Some/File/Path" -account AccountEmail -proxy "SomeIP"

此示例将在批处理文件中工作

SubprocessCommand = ['java', '-jar', 'Some/File/Path',
'-account RandomEmail@gmail.com', '-proxy "111.111.11.111"']
subprocess.Popen(SubprocessCommand, shell=True)

然而，这在python中是行不通的，有人知道我做错了什么吗？我的警告是

2021-04-05 14:13:47 [WARN] Unsupported quick start argument: -account RandomEmail@gmail.com
2021-04-05 14:13:47 [WARN] Unsupported quick start argument: -proxy "111.111.11.111"

Answer 1

尝试将所有参数分离为单独的列表项

SubprocessCommand = ['java', '-jar', 'Some/File/Path','-account', 'RandomEmail@gmail.com', '-proxy', '111.111.11.111']
subprocess.Popen(SubprocessCommand, shell=True)