擅长:python、mysql、java
<p>试试这个</p>
<p><a href="https://regex101.com/r/Khther/1" rel="nofollow noreferrer">^{<cd1>}</a></p>
<pre><code>import re
from itertools import groupby
print(
[list(v) for _, v in groupby(finalblobfpost1,
key=lambda x: re.search("\w\d+_\w{2}_\w{3}", x).group())]
)
</code></pre>
<hr/>
<pre><code>[['ABC/XYZ/16082020/K1_SS_ALM_222222_14082020.txt', 'ABC/XYZ/16082020/K1_SS_ALM_111111_14082020.txt'], ['ABC/XYZ/15082020/K1_AB_KIL_444444_15082020.txt', 'ABC/XYZ/15082020/K1_AB_KIL_333333_15082020.txt']]
</code></pre>