擅长:python、mysql、java
<p>以下方面应起作用:</p>
<pre><code>df = pd.read_csv("bracelet_no_variants.csv")
l=[i*1000 for i in range(len(df)//1000+1)]+[len(df)]
for i in range(len(l)-1):
temp=df.iloc[l[i]:l[i+1]]
temp.to_csv('bracelet_no_variants_'+str(l[i+1])+'.csv')
</code></pre>