我有一个元组列表。每个元组代表社交网络中的一个人。第一项是他们的id或“姓名”。第二是词典;每把钥匙都是网络中的另一个人,他们之间有着相互的联系,其价值是他们在一起有多少个相互关系
network = [
(6, {3: 3, 4: 3, 7: 2, 1: 3, 11: 2}),
(1, {7: 3, 11: 4, 6: 3, 4: 3}),
(4, {3: 2, 6: 3, 1: 3, 11: 2, 12: 3}),
(2, {9: 4, 8: 2, 10: 2, 5: 2}),
(12, {3: 2, 4: 3}),
(3, {5: 2, 8: 2, 12: 2, 4: 2, 7: 2, 6: 3}),
(10, {2: 2, 9: 3, 8: 3, 5: 2}),
(5, {3: 2, 8: 3, 9: 4, 10: 2, 2: 2}),
(13, {}),
(8, {2: 2, 9: 3, 10: 3, 3: 2, 5: 3}),
(7, {3: 2, 6: 2, 1: 3}),
(11, {1: 4, 6: 2, 4: 2}),
(9, {2: 4, 8: 3, 10: 3, 5: 4}),
]
如果两个人有1个、2个或3个相互关系,他们可能相互认识。如果他们有4个相互关系,他们可能相互认识。我希望处理此列表,以便确定谁可能/可能知道谁,结果如下:
Name: 1
Might know: 4, 6, 7
Probably knows: 11
Name: 2
Might know: 5, 8, 10
Probably knows: 9
Name: 3
Might know: 4, 5, 6, 7, 8, 12
Probably knows:
Name: 4
Might know: 1, 3, 6, 11, 12
Probably knows:
Name: 5
Might know: 2, 3, 8, 10
Probably knows: 9
Name: 6
Might know: 1, 3, 4, 7, 11
Probably knows:
Name: 7
Might know: 1, 3, 6
Probably knows:
Name: 8
Might know: 2, 3, 5, 9, 10
Probably knows:
Name: 9
Might know: 8, 10
Probably knows: 2, 5
Name: 10
Might know: 2, 5, 8, 9
Probably knows:
Name: 11
Might know: 4, 6
Probably knows: 1
Name: 12
Might know: 3, 4
Probably knows:
这是我目前用来处理它的代码:
might = []
probably = []
for person in network:
name = person[0]
connections = person[1]
for other_name, mutuals in connections.items():
if mutuals > 3:
probably.append(str(other_name))
else:
might.append(str(other_name))
但我最后只列出了两张清单:
['3', '4', '7', '1', '11', '7', '6', '4', '3', '6', '1', '11', '12', '8', '10',
'5', '3', '4', '5', '8', '12', '4', '7', '6', '2', '9', '8', '5', '3', '8',
'10', '2', '2', '9', '10', '3', '5', '3', '6', '1', '6', '4', '8', '10']
['11', '9', '9', '1', '2', '5']
我如何将这些与专有名称联系起来
您所期望的输出本质上是一个字典,因此将其构建为字典是有意义的。每个键都是一个名称;每个值将是另一个字典,带有键“maybe”和“maybly”。(其值均为列表。)
此时,我们可以使用Python的
pprint
函数来检查我们是否在正确的轨道上。(对于这样的嵌套结构,它比print
可读性强得多。)输出
(请注意,
pprint
会自动对要显示的键进行排序:它们实际上不是按那个顺序排列的。)现在我们所需要做的就是格式化它以便显示,不管我们怎么想。在这一点之前,我一直将名称保留为整数,这样我们就可以正确地对它们进行排序(并且不会像排序字符串时那样} 和list comprehensions。您可能知道也可能不知道f-strings,它也非常方便(甚至不要求变量是字符串!)
11
在2
之前结束)。如果这些赋值看起来很复杂,请查看^{输出:
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