我如何将一个Dataframe列一分为二,但要考虑到有时没有要拆分的内容,并且该值属于第二列?

2024-09-28 23:25:45 发布

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想象一下我有:

          COLUMN A
0    00000-UNITED STATES
1    01000-ALABAMA
2    01001-Autauga County, AL
3    01003-Baldwin County, AL
4    Barbour County, AL

我想将它们拆分为两列,但要确保如果最后一行中的值是字符串,它将转到第二列。如果是int,则转到第一列。例如,使用字符串:

          COLUMN B       COLUMN C
0          00000      UNITED STATES
1          01000         ALABAMA
2          01001     Autauga County, AL
3          01003     Baldwin County, AL
4                    Barbour County, AL

我试过这个:

df[['B','C']] = df.A.str.split(" - ", n = 1, expand=True)

很明显,它的反应是:

          COLUMN B       COLUMN C
0          00000      UNITED STATES
1          01000         ALABAMA
2          01001     Autauga County, AL
3          01003     Baldwin County, AL
4     Barbour County, AL


Tags: 字符串dfcolumnunitedintsplital想象
2条回答

您可以创建两个函数,从列A中提取所需的元素并分配给列B和列C:

def get_col_b(item):
    if '-' in item:
        return item.split('-')[0]
    else:
        return ''

def get_col_c(item):
    if '-' in item:
        return item.split('-')[1]
    else:
        return item

创建列,然后删除列A:

df['COLUMN B'] = df['COLUMN A'].apply(get_col_b)
df['COLUMN C'] = df['COLUMN A'].apply(get_col_c)
cols = ['COLUMN B', 'COLUMN C']
df = df[cols]

enter image description here

尝试使用^{}和正则表达式,使第二个捕获组成为可选-后面的值:

df[['B', 'C']] = df['A'].str.extract(r"(\d+$|\d+(?=\s*-))?(?:\s*-\s*)?(.+)?")
                          A       B                   C
0       00000-UNITED STATES   00000       UNITED STATES
1             01000-ALABAMA   01000             ALABAMA
2  01001-Autauga County, AL   01001  Autauga County, AL
3  01003-Baldwin County, AL   01003  Baldwin County, AL
4        Barbour County, AL     NaN  Barbour County, AL
5                     10234   10234                 NaN
6                32 Alabama     NaN          32 Alabama
7            432423 - state  432423               state

完整代码:

import pandas as pd

df = pd.DataFrame({
    'A': ['00000-UNITED STATES', '01000-ALABAMA',
          '01001-Autauga County, AL', '01003-Baldwin County, AL',
          'Barbour County, AL', '10234', '32 Alabama', '432423 - state']
})

df[['B', 'C']] = df['A'].str.extract(r"(\d+$|\d+(?=\s*-))?(?:\s*-\s*)?(.+)?")

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