python\uuu检测连续重复字符串

Question

我有这根绳子

"hellooooo my name is ooortda boooo"

detect_rept_str("o")

输出将是一个字符串的所有计数 连续重复多次

all_dtct=[5,3,4]

"my string".count()不适合我的需要

Answer 1

这样行吗

def count_adjacent_repeats(haystack, needle):
    if '' in (haystack, needle) or needle not in haystack:
        return []

    counts = []
    for s in haystack.split(needle)[:-1]:
        if s == '':
            if counts == []:
                counts.append(0)
            counts[-1] += 1
        else:
            counts.append(1)

    return counts