擅长:python、mysql、java
<p>首先,我不知道为什么要在一个列表上迭代两次。其次,如果您希望列表由空格定义,则需要将其拆分为元素,然后需要将每个项目转换为一个整数,然后可以迭代</p>
<pre><code>count_even = 0
count_odd = 0
numbers = input()
print(numbers)
for x in numbers.split():
if int(x) % 2 == 0:
count_even += 1
else:
count_odd += 1
print(count_even)
print(count_odd)
</code></pre>