python随机数生成器函数

Question

我有一个函数，它生成一个随机整数并在列表中追加，直到再次生成数字，如果它与列表中的数字匹配，则返回列表

from random import randint
def randomizerfinder(length):
    mylist = []
    is_done = False
    while (is_done == False):
        r = randint(1,length)
        is_found = False
        for n in mylist:
            if (n==r):
                is_found = True
                break
        if (is_found == False):
            mylist.append(r)
        if (len(mylist) == length):
            is_done=True
    return mylist

x=randomizerfinder(10)
print (x)

我是python的初学者。请建议我如何用较少的代码行精确地编写它

Answer 1

如评论中所述，您应该使用关键字in来减少if和您正在进行的评估：

from random import randint
def randomizerfinder(length):
    mylist = []
    r = randint(1,length)
    while (r not in mylist) and (length > len(mylist)):
      mylist.append(r)
      r = randint(1,length)
    return mylist
x=randomizerfinder(10)
print(x)

产出：

[2, 5, 8, 4, 10, 7]