2024-05-19 10:28:57 发布
网友
我想知道这里是否有专家的帮助。在python中,我想转换这个json。目前是:
{ "comics": "marvel", "comicname": [ "Spiderman", "Avengers", "Captain Marvel" ] }
我希望它是这样的。只有comicname列表:
{ "comicname": [ "Spiderman", "Avengers", "Captain Marvel" ] }
import json my_dict = { "comics": "marvel", "comicname": [ "Spiderman", "Avengers", "Captain Marvel" ] } # Remove unwanted key. del my_dict["comics"] # Turn dictionary into json string and print it. print(json.dumps(my_dict))
如果有时间,您应该检查一下json模块
你可以在这里做两件事。根据你的要求,我建议的第一个
代码1 删除“漫画”:“惊奇漫画”
x = { "comics": "marvel", "comicname": [ "Spiderman", "Avengers", "Captain Marvel" ] } del x["comics"] print(x)
代码2 仅显示“comicname”:列表[]
x = { "comics": "marvel", "comicname": [ "Spiderman", "Avengers", "Captain Marvel" ] } x = x["comicname"] print(x)
两个快速选项:
1-创建一个新对象
original_object = { "comics": "marvel", "comicname": [ "Spiderman", "Avengers", "Captain Marvel" ] } new_object = { 'comicname': original_object['comicname'] } print(new_object)
2-从原始漫画中删除“漫画”:
original_object = { "comics": "marvel", "comicname": [ "Spiderman", "Avengers", "Captain Marvel" ] } del original_object["comics"] print(original_object)
如果有时间,您应该检查一下json模块
你可以在这里做两件事。根据你的要求,我建议的第一个
代码1 删除“漫画”:“惊奇漫画”
代码2 仅显示“comicname”:列表[]
两个快速选项:
1-创建一个新对象
2-从原始漫画中删除“漫画”:
相关问题 更多 >
编程相关推荐