在Python中使用文本文件创建嵌套字典函数

Question

我试图创建一个嵌套的if函数，其中用户名是主字符串，其他的是子字符串。但由于某些原因，它没有分隔行，而是创建了多个嵌套字典，现在它只是停留在文本文件的第一行。Plz帮助

我的文本文件

shanm = null|Shanmugaraja|09/04/2002|0149606345|020409140817|0102393345|4770 4848 0109 0294
jiken = null|Soo Jiken|08/06/2000|0149600239|020908140213|011349780|8900 2828 1129 0889

我的嵌套字典代码

with open("something.txt", 'r') as f:
    data_dict = {}
    data_dict2 = {}
    data3 = {}
    for line in f:
        f.read()
        k, v = line.strip().split("=")
        listDetails = line.strip().split('|')
        data_dict = {"Full Name": listDetails[1]}
        data_dict.update({"Date of Birth": listDetails[2]})
        data_dict.update({"Phone Number": listDetails[3]})
        data_dict.update({"Identification Card (IC) Number": listDetails[4]})
        data_dict.update({"Emergency Contact Number": listDetails[5]})
        data_dict.update({"Credit /Debit Card Details ": listDetails[6]})
        data3[k] = data_dict
 print(data3)

期望输出

{'shanm ': {'Full Name': 'Shanmugaraja', 'Date of Birth': '09/04/2002', 'Phone Number': '0149606345', 'Identification Card (IC) Number': '020409140817', 'Emergency Contact Number': '0102393345', 'Credit /Debit Card Details ': '4770 4848 0109 0294'}}

{'jiken ': {'Full Name': 'Soo Ji', 'Date of Birth': '08/06/2000', 'Phone Number': '0149600239', 'Identification Card (IC) Number': '020908140213', 'Emergency Contact Number': '011349780', 'Credit /Debit Card Details ': '8900 2828 1129 0889'}}

收到的输出

{'shanm ': {'Full Name': 'Shanmugaraja', 'Date of Birth': '09/04/2002', 'Phone Number': '0149606345', 'Identification Card (IC) Number': '020409140817', 'Emergency Contact Number': '0102393345', 'Credit /Debit Card Details ': '4770 4848 0109 0294'}}
#NOT READING THE NEXT PART OF THE LINE

或（不带“F.READ（）”

{'shanm ': {'Full Name': 'Shanmugaraja', 'Date of Birth': '09/04/2002', 'Phone Number': '0149606345', 'Identification Card (IC) Number': '020409140817', 'Emergency Contact Number': '0102393345', 'Credit /Debit Card Details ': '4770 2828 0109 0394'}}
{'shanm ': {'Full Name': 'Shanmugaraja', 'Date of Birth': '09/04/2002', 'Phone Number': '0149606345', 'Identification Card (IC) Number': '020409140817', 'Emergency Contact Number': '0102393345', 'Credit /Debit Card Details ': '4770 2828 0109 0394'}, 'jiken ': {'Full Name': 'Soo Jiken', 'Date of Birth': '08/06/2000', 'Phone Number': '0149600239', 'Identification Card (IC) Number': '020908140213', 'Emergency Contact Number': '011349780', 'Credit /Debit Card Details ': '8900 2828 1129 0889'}}

把所有的东西都读一遍

Answer 1

看起来你想要一个字典列表。如果是这样，您可以这样做：

keys = ['Full name', 'Date of Birth', 'Phone Number',
        'Identification Card (IC) Number', 'Emergency Contact Number', 'Credit /Debit Card Details']

lod = []

with open('something.txt') as infile:
    for line in infile:
        key, v = line.split('=')
        d = {}
        for k, v in zip(keys, v.split('|')[1:]):
            d[k] = v
        lod.append({key.strip(): d})
for d in lod:
    name = list(d.keys())[0]
    print(d[name]['Full name']

Answer 2

keys = ["Full Name", "Date of Birth", "Phone Number",
        "Identification Card (IC) Number", "Emergency Contact Number",
        "Credit /Debit Card Details "]
data = {}
with open("something.txt", 'r') as f:
    for line in f:
        key, values = line.strip().split(" = ") # note the space around =, to avoid trailing space in key
        values = values.split('|')
        data[key] = dict(zip(keys, values[1:]))}

print(data)
print(data.get('jiken'))

可能您希望将每个dict data存储在某种容器类型中，如list

更新：我编辑了我的代码来创建一个dict，并通过用户名访问每个记录

Answer 3

请尝试将您的代码更新为：

with open("something.txt", 'r') as f:
    data_dict = {}
    data3 = {}
    for line in f.readlines():
        k, v = line.strip().split("=")
        listDetails = line.strip().split('|')
        data_dict = {"Full Name": listDetails[1]}
        data_dict.update({"Date of Birth": listDetails[2]})
        data_dict.update({"Phone Number": listDetails[3]})
        data_dict.update({"Identification Card (IC) Number": listDetails[4]})
        data_dict.update({"Emergency Contact Number": listDetails[5]})
        data_dict.update({"Credit /Debit Card Details ": listDetails[6]})
        data3[k] = data_dict
print(data3)