我一直在将python代码翻译成javascript,没有任何问题,但是对于下面的示例,我没有这样做,不知道原因是什么。尽管有类似的代码,javascript代码产生的输出似乎与python完全不同。我已经调查了这个问题,javascript似乎没有执行第二个递归分支?有人知道如何使javascript代码输出与python类似吗?谢谢
1-Python代码:
def createNode(_id, right, left):
return {'id': _id, 'left': left, 'right': right}
n1 = createNode(1, None, None)
n2 = createNode(2, None, None)
n3 = createNode(3, None, None)
n4 = createNode(4, None, None)
n5 = createNode(1, n1, n2)
n6 = createNode(2, n3, n4)
n7 = createNode(3, n5, n6)
def DownTree(lst, node):
left = node['left']
right = node['right']
if(right == None):
lst.append(node['id'])
else:
DownTree(lst, right)
if(left == None):
lst.append(node['id'])
else:
print('will excute')
DownTree(lst, left)
lst = []
DownTree(lst, n7)
print(lst)
## outputs: [1, 1, 2, 2, 3, 3, 4, 4]
2-Javascript代码:
function createNode(_id, right, left){
return {'id': _id, 'left': left, 'right': right}
}
n1 = createNode(1, undefined, undefined)
n2 = createNode(2, undefined, undefined)
n3 = createNode(3, undefined, undefined)
n4 = createNode(4, undefined, undefined)
n5 = createNode(1, n1, n2)
n6 = createNode(2, n3, n4)
n7 = createNode(3, n5, n6)
function DownTree(lst, node){
left = node['left']
right = node['right']
if(right == undefined){
lst.push(node['id'])
}
else{
DownTree(lst, right)
}
if(left == undefined){
lst.push(node['id'])
}
else{
console.log('not executed!')
DownTree(lst, left)
}
}
lst = []
DownTree(lst, n7)
console.log(lst)
// outputs: [1, 1, 1, 3]
在您的JS中
left
和right
的作用域不正确。您需要将var
或let
添加到它们的定义中,以便它们不是全局的相关问题 更多 >
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