在类中调用对象时,Int对象不可调用

2024-10-04 03:15:52 发布

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我正在制作一个有2艘宇宙飞船战斗的程序。到目前为止,它仍在工作,但当我们调用攻击函数时,会出现以下错误:

"TypeError: 'int' object is not callable on line 54"

我花了一段时间调试,但我不知道哪里出了问题。这里是代码:请提供一些建议,使其工作

import turtle
import time
import random
drawer = turtle.Turtle()
drawer.shape("square")
drawer.speed(0)
attacker = turtle.Turtle()
attacker.shape("square")
attacker.speed(0.5)
attacker.penup()

color1 = (random.randint(0, 255), random.randint(0, 255), random.randint(0, 255))
color2 = (random.randint(0, 255), random.randint(0, 255), random.randint(0, 255))

class spaceship:
  def __init__(self,name,health,attack,sheild,x,y):
    self.name = name
    self.health = health
    self.attack = attack
    self.sheild = sheild
    self.x = x
    self.y = y
  def draw_spaceship(self, color):
    drawer.color(color)
    drawer.penup()
    drawer.goto(self.x, self.y)
    drawer.begin_fill()
    for i in range(0,4):
      drawer.forward(100)
      drawer.right(90)
    drawer.end_fill()
  def attack(self, color, enemy_name):
    attacker.goto(self.x, self.y)
    attacker.goto(enemy_name.x, enemy_name.y)
    attacker.color(color)
    where_attack = random.randrange(0,2)
    if where_attack == 1:
      where_attack = "health"
      enemy_name.health -= self.attack
    else:
      where_attack = "sheild"
      enemy_name.sheild -= self.attack
    print(self.name,"is attacking the",where_attack,"of",enemy_name.name+".")
    print("Now",enemy_name.name,"has",enemy_name.health,"health.")

# draws spaceships
Noob = spaceship("Noob",random.randrange(100,500),random.randrange(10,200),random.randrange(10,200),-250,50)
Noob.draw_spaceship(color1)

Pro = spaceship("Pro",random.randrange(100,1000),random.randrange(100,500),random.randrange(10,200),100,50)
Pro.draw_spaceship(color2)

drawer.forward(2000)

Pro.attack(color1, Noob)

Tags: nameselfrandomwherecolordrawerrandinthealth
2条回答

问题是您正在声明spaceship的属性(变量)attack与其方法attack()相同。
由于Prospaceship的一个实例,当您在脚本末尾调用Pro.attack()时,实际上是在尝试调用其类型为int的属性

尝试将该方法的名称更改为其他名称

尝试重命名方法“攻击”,然后重试。似乎属性和方法是用相同的名称调用的

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