如何一次进行多个替换？|python

Question

我有以下字符串：

stringone = '0123456789 abcdefghijklmnopqrstuvwxys ABCDEFGHIJKLMNOPQRSTUVWXYS'

我需要做以下工作：

0 = s
1 = 6
2 = r
...
Z = F

但我需要马上做。我是说，不是

stringone.replace('0', 's')
stringone.replace('1', '6')

…不是那样，而是一行。比如说，我能做吗

stringone.replace('0', 's'; '1', '6')

我不知道怎么做。你能帮助我吗？ Python 3.6.0

Answer 1

请尝试以下操作：

import re

def multireplace(string, sub_dict):

    substrings = sorted(sub_dict, key=len, reverse=True)
    regex = re.compile('|'.join(map(re.escape, substrings)))
    return regex.sub(lambda match: sub_dict[match.group(0)], string)

stringone = '0123456789 abcdefghijklmnopqrstuvwxys ABCDEFGHIJKLMNOPQRSTUVWXYS'

sub_dict = {"0": "s", "1": "6", "2":"r","Z":"F"}
output = multireplace(stringone, sub_dict)

Answer 2

让我们用字典来做：

dic = {'0':'s', '1':'6', '2':'r'....}

# either join
''.join(i if i not in dic else dic[i] for i in stringone)

# or re
import re
re.compile("|".join(dic.keys())).sub(lambda m: dic[re.escape(m.group(0))], stringone)

Join更简单，因为我们用值替换键

Answer 3

>>> stringone.translate({ord('0'): 's', ord('1'): '6'})
's623456789 abcdefghijklmnopqrstuvwxys ABCDEFGHIJKLMNOPQRSTUVWXYS'