擅长:python、mysql、java
<p>埃姆拉的回答是好的。我只是想添加一个替代解决方案</p>
<pre><code>a=[['kyle','movie','c_13'],
['blair','food','a_29'],
['reese','phone','abc_76']]
b=['df.movie',
'ghk.food',
'qwe.phone']
b2 = [b_.split(".")[1] for b_ in b]
for item in range(len(a)):
if any(elem in a[item] for elem in b2):
print(a[item])
</code></pre>