有没有更快的方法
listOfClasses = [fooA, fooB, fooC]
setOfStrings = {c.string for c in listOfClasses}
newListOfClasses = []
for c in listOfClasses:
if c.string in setOfStrings:
newListOfClasses.append(c)
setOfStrings.remove(c.string)
限制/注意事项:
listOfClasses
:
newListOfClasses
:
listOfClasses
假设我有一节课
class Foo(object):
def __init__(self,string):
self.string = string
还有一个类列表,我想在其中删除所有具有重复“string”实例变量的类
fooA = Foo("alice")
fooB = Foo("alice")
fooC = Foo("His Royal Highness The Prince Philip, Duke of Edinburgh, Earl of Merioneth, Baron Greenwich, Royal Knight of the Most Noble Order of the Garter, Extra Knight of the Most Ancient and Most Noble Order of the Thistle, Member of the Order of Merit, Grand Master and First and Principal Knight Grand Cross of the Most Excellent Order of the British Empire, Knight of the Order of Australia, Additional Member of the Order of New Zealand, Extra Companion of the Queen’s Service Order, Royal Chief of the Order of Logohu, Extraordinary Companion of the Order of Canada, Extraordinary Commander of the Order of Military Merit, Lord of Her Majesty’s Most Honourable Privy Council, Privy Councillor of the Queen’s Privy Council for Canada, Personal Aide-de-Camp to Her Majesty, Lord High Admiral of the United Kingdom.")
listOfClasses = [fooA, fooB, fooC]
在这里,我想删除fooA
或fooB
(不管是哪一个),这样我只剩下
listOfClasses = [fooB, fooC] # for example
到目前为止,我有以下几点:
setOfStrings = {c.string for c in listOfClasses}
newListOfClasses = []
for c in listOfClasses:
if c.string in setOfStrings:
newListOfClasses.append(c)
setOfStrings.remove(c.string)
对于以上内容,我得到了以下时间安排:
# len(listOfClasses) = 3
2.22 ms ± 24.5 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
# len(listOfClasses) = 20
2.29 ms ± 119 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
在听写理解中使用字典的唯一键应该非常快:
完整示例:
相关问题 更多 >
编程相关推荐