如何匹配文本文件中的两个模式(选择包含“205”和“212”的两行),如下所示并获取它们。 现在我的代码是只得到一个模式的结果。谢谢大家
pattern = re.compile(r"^\S+ \S+ \S+ ([205][212])\d+.*$")
mpls switch-l2vc 10.123.143.209 205316002 tunnel-policy TE between 10.123.130.1 205316004 tunnel-policy TE backup 10.123.130.2 205316004 tunnel-policy TE encapsulation vlan
mpls switch-l2vc 10.124.17.165 205315402 tunnel-policy TE between 10.123.130.1 205315404 tunnel-policy TE backup 10.123.130.2 205315404 tunnel-policy TE encapsulation vlan
mpls switch-l2vc 10.124.18.113 212359002 tunnel-policy TE between 10.123.130.1 205359004 tunnel-policy TE backup 10.123.130.2 205359004 tunnel-policy TE encapsulation vlan
mpls switch-l2vc 10.124.17.161 212315002 tunnel-policy TE between 10.123.130.1 205315004 tunnel-policy TE backup 10.123.130.2 205315004 tunnel-policy TE encapsulation vlan
mpls switch-l2vc 10.124.17.168 205315702 tunnel-policy TE between 10.123.130.1 205315704 tunnel-policy TE backup 10.123.130.2 205315704 tunnel-policy TE encapsulation vlan
你需要
见regex demo详细信息:
^
-字符串的开头\S+ \S+ \S+
-三个单空格分隔的单词(?:205|212)
-要么{\d
-位.*$
行的其余部分,字符串的结尾李>尝试以下模式:
(?=(^.*205))(?=(.*212.*$))|(?=(^.*212))(?=(.*205.*$))
代码:
输出:
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