根据条件造句

Question

这是输入Dict，我从中导出并生成了一个句子

输入

indexes={'Laptops':'1','Mob':'2','Cars':'3','Bus':4}
    Notes={
 

   
    'indexs':[1,3],
    'Laptops':[
        "dell","asus","acer"
    ],
    'Mob':[
        "mi","realme"
    ],
   'Bus':[
     "aB"
 
   ],
    'Cars':["Not found"
         ]

}

创建了一个句子生成器以生成句子：

def SenGen(alpha,beta):
    for a,b in alpha.items():
        for c,d in beta.items():
            if c in a:
                print(f"{a} are ", end="")
                for i, e in enumerate(b):
                    if i == len(b)-1:
                        print(f"and {e}. ", end="")
                    elif i == len(d)-2:
                        print(f"{e} ", end="")
                    else:
                        print(f"{e}, ", end="") 

在这个函数的帮助下，我生成了一个句子

SenGen(Notes,indexes)

输出

Laptops are dell, asus, and acer. Mob are mi, and realme. Bus are and aB. Cars are and not found. 

在上面的句子中，Bus中只有一个值，即aB，但在生成的中，我将其作为“Bus are和aB”，对于汽车，它生成为“未找到汽车”

但预期输出应如下所示：

Laptops are dell, asus, and acer. Mob are mi, and realme. Bus is aB. Cars are not found.

公共汽车是aB型，汽车不是

请帮助我编写代码，以及如何为案例1即兴编写代码

案例2：

input indexes={'Laptops':'1','Mob':'2','Cars':'3','Bus':4}

Notes={
    
    'indexs':[1,3],
    'Laptops':[
        "dell","asus","acer"
    ],
    'Mob':[
        "mi","realme"
    ],
   'Bus':[
     "aB"
 
   ],
    'Cars':[
         ]

}

在案例2中，我知道cars的值为空，输出如下所示

输出

Laptops are dell, asus, and acer. Mob are mi, and realme. Bus are and aB. Cars are 

期望输出：

Laptops are dell, asus, and acer. Mob are mi, and realme. Bus is aB. Cars are not found.

请帮助我编写代码，以及如何即兴编写案例2的代码

我厌倦了以下情况：

1.if i == len(b)==1:
                            
    print(f" is {e} ", end="")

2.if i == len(b)==0:
                            
    print(f" is {e} ", end="")
3.if i == len(b)<1:
                            
    print(f" is {e} ", end="")
4.if i == len(b)>1:
                            
    print(f" is {e} ", end="")

                

我的输出没有变化，我的输出保持如下

Laptops are dell, asus, and acer. Mob are mi, and realme. Bus are and aB. Cars are

Answer 1

你做错了的是你从来没有考虑过某些情况。 这是函数的修改版本；我写了一些评论来解释你忘记的案例：

def SenGen(alpha,beta):
    for a,b in alpha.items():
        for c,d in beta.items():
            if c in a:
                # in case the value of some key is empty (like Cars in your case)
                if b == []:
                    print(f"{a} are not found.")
                if len(b) > 1:
                    print(f"{a} are ", end="")
                for i, e in enumerate(b):
                    # in case the key has only one value, which might be "Not found" or some other value
                    if len(b) == 1:
                        if "Not found" in b:
                            print(f"{a} are {e}. ", end="")
                        else:
                            print(f"{a} is {e}. ", end = "")
                    # in case the key has more than one value
                    else:
                        if i == len(b)-1:
                            print(f"and {e}. ", end="")
                        elif i == len(d)-2:
                            print(f"{e} ", end="")
                        else:
                            print(f"{e}, ", end="")