如何卸下支架和支架内的编号？

Question

我写了这段代码，但它没有给我正确的答案。请帮帮我

for text in hiv2['Number of deaths due to HIV/AIDS']:
   a=text.replace(' ','')
   b=a.split('[')
hiv2['Number of deaths due to HIV/AIDS']=b[0]

Answer 1

使用.str.replace

df['col_name'] = df['col_name'].str.replace(r"\[.*\]","")