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<p>我有一本字典:
元组的最后一个条目是射门的分钟数。
例如:奥斯卡一名巴西球员在第90分钟射门得分</p>
<pre><code>players = {
"Brazil": [
(12, "Júlio César", "Goalkeeper", []),
(4, "David Luiz", "Defender", []),
(6, "Marcelo", "Defender", []),
(13, "Dante", "Defender", []),
(23, "Maicon", "Defender", []),
(5, "Fernandinho", "Midfielder", []),
(7, "Hulk", "Midfielder", []),
(8, "Paulinho", "Midfielder", []),
(11, "Oscar", "Midfielder", [90]),
(16, "Ramires", "Midfielder", []),
(17, "Luiz Gustavo", "Midfielder", []),
(19, "Willian", "Midfielder", []),
(9, "Fred", "Striker", []),
],
"Germany": [
(1, "Manuel Neuer", "Goalkeeper", []),
(4, "Benedikt Höwedes", "Defender", []),
(5, "Mats Hummels", "Defender", []),
(16, "Philipp Lahm", "Defender", []),
(17, "Per Mertesacker", "Defender", []),
(20, "Jérôme Boateng", "Defender", []),
(6, "Sami Khedira", "Midfielder", [29]),
(7, "Bastian Schweinsteiger", "Midfielder", []),
(8, "Mesut Özil", "Midfielder", []),
(13, "Thomas Müller", "Midfielder", [11]),
(14, "Julian Draxler", "Midfielder", []),
(18, "Toni Kroos", "Midfielder", [24, 26]),
(9, "André Schürrle", "Striker", [69, 79]),
(11, "Miroslav Klose", "Striker", [23]),
],
}
</code></pre>
<p>我想创建一个函数,该函数将团队和一分钟作为输入,并返回该分钟内射门的目标数。
我这样试过:</p>
<pre><code>def score_at_minute(team,minute):
global players
goals = [goals for (number, player, position, goals) in players[team] if len(goals)>=1]
goals_1 = [goal[0] for goal in goals if len(goal)>=1 if goal[0] <= minute]
goals_2 = [goal[1] for goal in goals if len(goal) ==2 if goal[1]<= minute]
all_goals = goals_1+goals_2
return len(all_goals)
</code></pre>
<p>我的函数调用如下所示:</p>
<pre><code>score_at_minute("Germany",90)
</code></pre>
<p>有没有更简单的方法,或者最好的方法是一行呢</p>