擅长:python、mysql、java
<p>将<code>\d</code>放入字符列表,并将<code>{3}</code>更改为<code>{2,}</code>如何:</p>
<pre><code>df['Lab'] = df['Sentence'].str.findall(r'([a-zA-Z\d])\1{2,}').astype(bool).astype(int)
</code></pre>
<p>输出:</p>
<pre><code> Sentence Lab
0 are they saddddd? 1
1 I don't want to go 0
2 heyyyyy 1
3 12333 1
4 00unit 0
5 00wolf 0
6 01man 0
7 20595 0
8 2091996 0
9 03dumbdumb 0
</code></pre>