在python中使用回车符和换行符的正确方法

Question

问题

在我用python编写代码的两年中，我一直在努力解决这个问题，因此我想寻求正确的方法。如何使其覆盖上一次打印，同时使用换行符（通过返回或\n）。我已经尝试了我能找到的大多数答案，但是它只做了我想做的工作之一

---

测试模型

import time, sys

counter1 = 0
counter2 = 0
counter3 = 0

for i in range(5):
    time.sleep(0.1)
    counter1 += 1
    counter2 += 1
    counter3 += 1
    
    #print method here!

---

尝试1:

使用"""和\r的多行（f）字符串

    print(f"""\r
Counter 1: {counter1}
Counter 2: {counter2}
Counter 3: {counter3}
    """)

尝试1的输出：

Counter 1: 1
Counter 2: 1
Counter 3: 1


Counter 1: 2
Counter 2: 2
Counter 3: 2

..etc

---

尝试2:

使用\r和\n的正规（f）字符串

print(f"\rCounter 1: {counter1}\nCounter 2: {counter2}\nCounter 3: {counter3}")

尝试2的输出：

Counter 1: 1
Counter 2: 1
Counter 3: 1
Counter 1: 2
Counter 2: 2
Counter 3: 2
etc..

---

尝试3:

使用sys.stdout.write、\r和\n

sys.stdout.write(f'\rCounter 1: {counter1}\nCounter 2: {counter2}\nCounter 3: {counter3}')
sys.stdout.flush()  

尝试3的输出：

Counter 1: 1
Counter 2: 1
Counter 1: 2
Counter 2: 2
Counter 1: 3
etc..

---

尝试4:

在末尾使用回车符（\r）：

print(f"Counter 1: {counter1}\nCounter 2: {counter2}\nCounter 3: {counter3}\n", end = "\r")

尝试4的输出：

Counter 1: 1
Counter 2: 1
Counter 3: 1
Counter 1: 2
Counter 2: 2
Counter 3: 2

---

尝试5:

彼此分开打印，第一个打印前有\r

print(f"\rCounter 1: {counter1}")
print(f"Counter 2: {counter2}")
print(f"Counter 3: {counter3}")

尝试5的输出：

Counter 1: 1
Counter 2: 1
Counter 3: 1
Counter 1: 2
Counter 2: 2
Counter 3: 2

Answer 1

再加上alefir的回答，我能想到的最接近的是这样的东西，它把你想要改变的一切都放在一行上。不确定它是否满足代码的需要

import time

counter1 = 0
counter2 = 0
counter3 = 0

print("%s\t%s\t%s" % ("Counter 1 name", "Counter 2 name", "Counter 3 name"))
for i in range(5):
    time.sleep(0.1)
    counter1 += 1
    counter2 += 1
    counter3 += 1
    print("%.1f\t\t%.1f\t\t%.1f" % (counter1, counter2, counter3), end = "\r")

或者，要用多行实现alefir的方法，您可以使用一些like this to clear the screen：

# import only system from os
from os import system, name

# define our clear function
def clear():
  
    # for windows
    if name == 'nt':
        _ = system('cls')
  
    # for mac and linux(here, os.name is 'posix')
    else:
        _ = system('clear')

结合您的第1次尝试，您将得到如下结果：

for i in range(5):
    time.sleep(0.1)
    counter1 += 1
    counter2 += 1
    counter3 += 1
    clear()
    print(f"""\r
    Counter 1: {counter1}
    Counter 2: {counter2}
    Counter 3: {counter3}
    """)