当有人破坏我的库时,我会引发一个自定义异常,当前的情况如下:
Traceback (most recent call last):
File "main.py", line 17, in <module>
StateMachine()
File "main.py", line 15, in __new__
activate(self)
File "/home/runner/va4un94x2qp/fsm.py", line 101, in activate
state = enable(machine, state)
File "/home/runner/va4un94x2qp/fsm.py", line 94, in enable
raise MissingReturnError("State '{}' in machine '{}' missing a return statement, or it returns None..".format(StateFound.fallmsg, machine.__name__))
fsm.MissingReturnError: State '__main__' in machine 'StateMachine' missing a return statement, or it returns None.
但我希望它看起来像这样:
Traceback (most recent call last):
File "main.py", line 17, in <module>
StateMachine()
File "main.py", line 15, in __new__
activate(self)
MissingReturnError: State '__main__' in machine 'StateMachine' missing a return statement, or it returns None.
我如何做到这一点,没有任何例外的胡说八道?(因为那不仅影响一个异常,还影响所有异常)我想修改一个异常。顺便说一句,我已经尝试将suppress\u context设置为True,并尝试从None中引发异常。我还能怎么做呢
如果你问,我想要的一切都不需要了。所需要的只是异常消息和activate()方法的调用
我不会搞乱Python解释器,我将向公众发布这个库,我希望每个人都能看到异常。(它是Python 3.X)
目前没有回答
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