来自的Django模型创建新记录，而不是更新旧记录

Question

我是Django的初学者。我的问题是我正在更新我的记录，但它正在添加一个新记录，而不是更新旧记录

我哪里出错了

视图.py

class EditProduct(TemplateView):
    template_name = 'stock/editproduct.html'

    def get(self, request, product_id):
        productedit = get_object_or_404(Product, pk=product_id)
        data=Product.objects.get(id=product_id)
        form = EditProductForm(instance=data)
        args = {'form':form, 'productedit':productedit}
        return render(request, self.template_name, args)

    def post(self, request, product_id):
        form = EditProductForm(request.POST, request.FILES)
        if form.is_valid():
            productadded = form.save(commit=False)
            productadded.saler =  request.user
            productadded.pub_date = timezone.datetime.now()
            productadded.save()
            return redirect('stock')
        else:
            args = {'form': form}
            return render(request, self.template_name, args)

Answer 1

我假设stock是包含views.py、models.py、url.py的应用程序/文件夹的名称

views.py有关UpdateViews的文档，请参见here

from django.views.generic import UpdateView
from django.utils import timezone
from stock.models import Product
from stock.forms import EditProductForm 

Class ProductUpdateView(UpdateView):
    model = Product
    form_class = EditProductForm
    success_url = reverse_lazy('stock:product_list')
    template_name = 'stock/editproduct.html'

    def form_valid(self, form):
        form.instance.saler =  self.request.user
        form.instance.pub_date = timezone.now()
        return super().form_valid(form)

url.py

from stock import views

app_name = 'stock'
urlpatterns = [
    path('product/update/<int:pk>', views.ProductUpdateView.as_view(), name='product_update'),
    path('product/list', views.ProductListView.as_view(), name='product_list'
]

下面的代码片段可以添加到要更新的产品页面的html中，这通常是由details views类或函数生成的产品详细信息页面

在该页面上添加一个按钮，将您带到更新页面，并传入您要更新的产品的id

<a class="btn btn-outline-warning waves-effect" href="{% url 'stock:product_update' pk=product.pk %}"> Update product</a>