在我的列表理解中，“for”循环的语法有什么错误吗？

Question

如果这是正确的

v = [22, 13, 45, 50, 98, 69, 43, 44, 1]
[ (x+1 if x >=45 else x+5)  for x in v ]

那么这个代码怎么了

def isPrime(num):
is_prime = False
if num > 1:
    for i in range(2, num):
        if (num % i) == 0:
            is_prime = False
            break
    else:
        is_prime = True
else:
    is_prime = False
return is_prime


listTablesOnlyPrimes = [[ (i*num if isPrime(i*num)==True else pass) for i in range(1, 11)] for num in range(1, 11)]
for listTable in listTablesOnlyPrimes:
    print(listTable)

我想知道解释器在消息中的SyntaxError是什么：

listTablesOnlyPrimes = [[ (i*num if isPrime(i*num)==True else pass) for i in range(1, 11)] for num in range(1, 11)]
                                                                  ^
SyntaxError: invalid syntax

Answer 1

问题在于嵌套列表中的if条件

listTablesOnlyPrimes = [[ (i*num) for i in range(1, 11) if isPrime(i*num)==True] for num in range(1, 11)]

注意：

Your code always return empty lists I don't understand why are you doing this i * num never become prime if i > 1