如果标签只有一个，Find（Beautiful Soup）将返回None

Question

有谁能帮我理解这个现象吗？”如果标记只有一个，则find'返回None。（我已经试过“lxml”，但没有用）。这是我在IDE中正在做和接收的部分：

>>> driver = webdriver.Chrome("D:\\Text documents\\for work\\English project\\chromedriver")
>>> driver.get('https://www.interactive-english.ru/uprazhneniya/408-conditionals-exercise/')
>>> content = driver.page_source
>>> soup = BeautifulSoup(content, 'lxml')
>>> FullList = soup.findAll(['ol', 'h4', 'h5']);
>>> htmlF = FullList[1]

>>> htmlF

<ol> <li> Perhaps one day a cat will follow you home.<br /> What would you do... </li> <li> Perhaps one day somebody will ask you to sing your favourite song.<br /> What would you do... </li> <li> Perhaps one day you will find a hidden treasure.<br /> What would you do... </li> <li> Perhaps one day somebody will throw an egg at you.<br /> What would you do... </li> <li> Perhaps one day your car will be stolen.<br /> What would you do... </li> </ol>

Answer 1

你什么时候做的

htmlF = FullList[1]

检索到的顶层是ol标记。它里面没有嵌套的ol，这就是为什么在调用.find('ol')时会得到None

您可以通过以下方式进行检查：

print(htmlF.name)  
>> 'ol'

你能行

htmlF.find('li') 

例如，要获取第一个子元素作为li是您设置为htmlF的父元素ol中的子元素

Answer 2

尝试：

soup = BeautifulSoup(content, 'html.parser')
FullList = soup.findAll(['ol', 'h4', 'h5']);
for fl in FullList:
    print(fl)

它为我找到了所有元素