擅长:python、mysql、java
<p>这应该足以让您开始:</p>
<pre><code>x = "vnu4)rhg&3j"
h_ind = x.find('h')
for i in range(len(x)):
print(f"{x[i]} = {i - h_ind}")
</code></pre>
<p><code>x.find(h)</code>正在获取字符串中“h”的索引,然后从其他字符的索引中删除</p>
<p>输出:</p>
<pre><code>v = -6
n = -5
u = -4
4 = -3
) = -2
r = -1
h = 0
g = 1
& = 2
3 = 3
j = 4
</code></pre>
<p>这现在适用于:</p>
<pre><code>x = "vvnu4)rhg&3j"
</code></pre>
<p>输出:</p>
<pre><code>v = -7
v = -6
n = -5
u = -4
4 = -3
) = -2
r = -1
h = 0
g = 1
& = 2
3 = 3
j = 4
</code></pre>