（Python）即使在满足条件的情况下也在执行ELSE？

Question

我正在做作业，但是有点卡住了，为什么代码执行“else”甚至认为“if”已经满足了呢？忽略这些草率的代码，我是新来的：/

order1 = input("What would you like to order?: \n \n" + "1: " + orderBurger + "\n" + "2: " + orderFries + "\n" + "3: " + orderDrink + "\n" + "\nAnswer = ")

while order == True:
 if order1 == 1:
  print("You have selected to order 1: " + orderBurger)
 elif order1 == 2:
  print("You have selected to order 1: " + orderFries)
 elif order1 == 3:
  print("You have selected to order 1: " + orderDrink)
 else:
  print("Invalid Input")
 check = input("Is this your final item?:" + "1: " + q1 + "2: " + q2  + "Answer = ")
 if check == 1:
  print("Your items have been added to the basket")
  break
 elif check == 2:
  check
 elif check == 3:
  check
 else:
  print("Invalid input")

This is the output

Answer 1

如果您使用type(order1)，您将看到您的答案是字符串还是int。如果它是字符串（我认为是），您可以使用int(order1)将其转换为int，或者将代码替换为if order1 == '1'