如何将非常特殊的列表导出到excell或csv

Question

嘿，我有一张这样的清单：

['192.168.0.1  switch1 ff:ff:ff:ff:ff:ff  657 dynamic port:42','10.60.37.2 switch1 ff:ff:ff:ff:ff:ff  657 dynamic port:41','192.168.0.240  switch1 ff:ff:ff:ff:ff:ff  657 dynamic port:40']

当我导出到excell时，每个块都在不同的行中，这很好，但都在同一行中，我希望在第1列中有地址，在第2列中切换，等等

                                 excel colunm 1
excel row1: 192.168.0.1  switch1 ff:ff:ff:ff:ff:ff  657 dynamic port:42
excel row2: 10.60.37.2   switch1 ff:ff:ff:ff:ff:ff  657 dynamic port:41
excel row3 :192.168.0.240  switch1 ff:ff:ff:ff:ff:ff  657 dynamic port:40

所以我想要这样

          exlcol1        exlcol2       exl.col3     exl.col4 exl.col5 exl.col6 
exlrow1: 192.168.0.1     switch1   ff:ff:ff:ff:ff:ff   657   dynamic    port:42
exlrow2: 10.60.37.2      switch1   ff:ff:ff:ff:ff:ff   657   dynamic   port:41
exlrow3 :192.168.0.240   switch1   ff:ff:ff:ff:ff:ff   657   dynamic   port:40

我尝试将其导出到csv，但它说wtr.writerows（行）必须是byte.object，就像，然后我尝试将列表更改为字符串以将其更改为byte.object，但它说我的wtr.writerows（行）应该是可交互的

这是我用来导出到csv的代码

import csv
with open('test.csv', 'wb') as f:
     wtr = csv.writer(f, delimiter= ',')
     for row in data11parts1:
        wtr.writerows(row)

with open('test.csv', 'r') as f:
    for line in f:
         print (line)

我倾向于将其导出到excell，但我认为这有助于更好地解释我的问题和我拥有的数据类型。 我只是想告诉你，我从这个附加中获得了我的data11parts1：

for element in data2:
    elementstring=''.join(element)
    for element in res1:
        elementstring5=''.join(element)
        if elementstring in elementstring5:
             with open(Sw1, 'r') as f3:
              for line5 in f3:
               if elementstring in line5:
                  print('managemnet-tool' + ' - ' + Sw1.rsplit('.txt',1)[0] + ' - ' + elementstring5.rsplit('-', 1)[0] + ' - ' + line5.rsplit('\n', 1)[0])
                  data11.append(elementstring5.rsplit('-',1)[0] + '  ' + Sw1.rsplit('.txt',1)[0] + ' ' + line5.rsplit('\n', 1)[0])
                  data13.append(str(line5.rsplit('\n', 1)[0]))
                  exit

Answer 1

它抱怨是因为您打开文件进行二进制写入。CSV编写很简单，将内部字符串拆分为列表（在空格处拆分）并编写：

data = ['192.168.0.1  switch1 ff:ff:ff:ff:ff:ff  657 dynamic port:42',
        '10.60.37.2 switch1 ff:ff:ff:ff:ff:ff  657 dynamic port:41',
        '192.168.0.240  switch1 ff:ff:ff:ff:ff:ff  657 dynamic port:40']

# split the strings into their columns
dp = [d.split() for d in data]

import csv
with open("data.txt","w", newline="") as f:    # w not wb and supply newline
    writer = csv.writer(f)

    # write em all
    writer.writerows(dp)

with open("data.txt") as f:
    print(f.read())

文件内容：

192.168.0.1,switch1,ff:ff:ff:ff:ff:ff,657,dynamic,port:42
10.60.37.2,switch1,ff:ff:ff:ff:ff:ff,657,dynamic,port:41
192.168.0.240,switch1,ff:ff:ff:ff:ff:ff,657,dynamic,port:40

看

• str.split()
• csv.writer()