我需要从python的列表中提取每个字典？

Question

因此，我有一个API，它返回一个列表（示例！）==>

words = [[{'aaa':'123', 'bbb':'456',.....}, {'ccc':'123', 'ddd':'456',.....}, {'eee':'123', 'fff':'456',.....}]]

我需要删除嵌套列表==>

word = [{'aaa':'123', 'bbb':'456',.....}, {'ccc':'123', 'ddd':'456',.....}, {'eee':'123', 'fff':'456',.....}]

如何在python中实现它

Answer 1

尝试：

import ast
words = ast.literal_eval(words)[0]

Answer 2

由于嵌套列表只是上级列表的第一项，因此您可以直接拉取该上级列表的第一项

word = words[0]

Answer 3

您可以使用列表理解：

words = [[a], [b], [c], [d]]
flattened = [val for sublist in words for val in sublist]