如何通过相同的函数重新启动函数？

Question

如何通过函数本身重新启动函数？下面是函数的内容：

class thingamajig():
    def __init__(self):
        pass
    def dostuff(self):
        number = random.randint(0, 3)
        if number == 3:
            #restart here??????
thing = thingamajig()
thing.dostuff()

如何重新启动该功能

Answer 1

在dostuff中创建while循环，例如：

def dostuff(self):
    whatever you need the code to do
    doagain = input('Want to do this again? y/n ')
    while doagain != 'n':
        whatever you need the code to do
        doagain = input('Want to do this again? y/n ')

注意，必须使用C++中的D/while循环来解决必须重新编码代码的问题，但对于Python

则如此。

Answer 2

这就是你如何做到的：

class thingamajig():
    def __init__(self):
        pass
    def dostuff(self):
        number = random.randint(0, 3)
        if number == 3:
            self.dostuff()
thing = thingamajig()
thing.dostuff()

这个类只知道它的参数和它自己的变量。Self是一个会说“this class”的关键字

Answer 3

那么：

class thingamajig():
    def __init__(self):
      pass
    def dostuff(self):
        doagain = input('Want to do this again? y/n ')
        if doagain == 'y':
            self.dostuff()
thing = thingamajig()
thing.dostuff()