从一手7张牌中提取对

Question

我正在用Python编写代码来创建一个GoFish游戏，在这个游戏中，您需要的不是一种类型的四个，而是成对的。我用python编写了一段代码，在一张7张卡片的手里找到成对的卡片。代码给出了所有对的列表（因此它是列表的列表）。由于我是Python新手，我想知道是否有更有效的方法来实现我的代码

这是我写的代码。最终，它将成为类中的一个函数

#hand = ['D2', 'S1', 'D3', 'H1', 'C1', 'H5', 'D5']
#hand = ['D1', 'S1', 'S2', 'H2', 'C1', 'H5', 'D5']
#hand = ['D1', 'S1', 'S2', 'H1', 'C1', 'H5', 'D5']
hand = ['D1', 'S1', 'C1', 'H1', 'C2', 'H2', 'D5']
#hand = ['D2', 'S1', 'C3', 'H4', 'C5', 'H6', 'D7']

list_of_pairs = []
i=0
while i < len(hand):
    current_pos = i
    for k in range(i+1, len(hand)):
        card_1 = hand[i]
        card_2 = hand[k]
        if card_1[-1:] == card_2[-1:]:
            pair_2 = hand.pop(k)
            pair_1 = hand.pop(i)
            pair = [pair_1, pair_2] 
            list_of_pairs.append(pair)
            i = current_pos - 1
            break
    i +=1 

print(f"List of pairs is {list_of_pairs}")
print(f"Left over hand is {hand}")

Answer 1

hand = [1,1,2,2,3,4,5,6,7,7,8,9,9]
hand_set = set()
pairs = set()
for card in hand:
    if card in hand_set:
        pairs.add(card)
    else:
        hand_set.add(card)

如果可以使用两对相同的卡

from collections import Counter
hand = [1,1,1,1,2,2,3,3,4,4,5,5,6,7,8,9,9,9,9]
card_counter = Counter()
for card in hand:
    card_counter[card]+=1

pairs = []
for k in card_counter:
    for i in range(int(card_counter[k]/2)):
        pairs.append([k,k])