“while”循环未按预期运行

Question

背景：

我已经做了一个程序，它接受文本输入，应用加密（一个简单的密码），并将输出保存到列表中——如果需要的话。消息也可以被解密

通过选项菜单导航程序： 1.加密消息 2.查看加密邮件 3.解密消息

为了允许程序的所有部分访问相同的已保存消息列表（变量），我在一个类中编写了它。类中存在调用此列表的def

到目前为止，只写入了“加密消息”位

问题：

用户决策流程由两个Y/N选项组成。 但是，这些选择不起作用——即使用户在“N”中键入，我的程序认为他们在这两种情况下都键入了“Y”

def encrypt():
    def save_cip():#This function allows the user to save the ciphered message to the ciphered_messages if they choose
        choosing = True
        while choosing:
            save_choice = input("Would you like to save your Ciphered message? (Y/N)\n")
            if save_choice == "Y" or "y":
                print("You chose yes")
                cct.ciphered_messages.append(' '.join(["Message", str(len(cct.ciphered_messages)), ":", cipher]))
                choosing = False
            elif save_choice == "N" or "n":
                print("You chose no")
                choosing = False
                continue
            else:
                print("That was not a valid entry, please enter Y or N only")
                continue

我认为问题出在范围内，在设置和读取Y或N时，不知何故，同一个变量没有被引用。我在同一个代码上下移动了大约3个小时，但仍然一无所获，在许多不同的地方声明了所有变量，没有运气，因此非常感谢任何建议

完整的可执行代码：

class cct:

print("Welcome to the CaeserCipher tool v1.0")
menu_state = "main" #This is used to record what state the program is in
unciphered_messages = [] #Decrypted messages are saved here
ciphered_messages = [] #Encrypted messages are saved here

def menu(): #This is the main menu interface
    while cct.menu_state == "main": #This while 
        cct.menu_state = input("What would you like to do? \n 1: Encrypt a Message \n 2: View Encrypted Messages \n 3: Decrypt a message\n")
        if cct.menu_state == "1":
            cct.encrypt()
        elif cct.menu_state == "2":
            cct.view()
        elif cct.menu_state == "3":
            cct.decrypt()
        elif cct.menu_state == "main":
            print("\n\nWelcome back to the menu!\n\n")
        else:
            print("You did not enter a valid choice. Please enter a number between 1 and 3.\n")
            cct.menu_state = "make_choice"
        continue

def encrypt():
    def save_cip():#This function allows the user to save the ciphered message to the ciphered_messages if they choose
        choosing = True
        while choosing:
            save_choice = input("Would you like to save your Ciphered message? (Y/N)\n")
            if save_choice == "Y" or "y":
                print("You chose yes")
                cct.ciphered_messages.append(' '.join(["Message", str(len(cct.ciphered_messages)), ":", cipher]))
                choosing = False
            elif save_choice == "N" or "n":
                print("You chose no")
                choosing = False
                continue
            else:
                print("That was not a valid entry, please enter Y or N only")
                continue

    #This while loop continually takes messages, gives the option of saving, and asks if you want to cipher another
    while cct.menu_state == "1":   
        text = input("Enter your message: ") #Enter the message you wish to cipher
        cipher = '' #Create a string for the cipher
        for char in text: #This for sub-loop will increment each character by 1. e.g. A -> B, T -> U, Z -> A
            if not char.isalpha():
                continue
            char = char.upper()
            code = ord(char) + 1
            if code > ord('Z'):
                code = ord('A')
            cipher += chr(code)
        print(' '.join(["Your ciphered message is:", cipher]))
        save_cip()
        print(cct.ciphered_messages)
        #This sub-while loop is reponsible for checking if you want to cipher another message
        #and making sure the user has made a valid choice
        choosing_another = True
        while choosing_another == True:
            choice_variable = input(' '.join(["You have", str(len(cct.ciphered_messages)), "saved messages \n", "Would you like to Cipher another? (Y/N)\n"]))
            if choice_variable == "Y" or "y":
                print("You chose yes")
                choosing_another = False
            elif choice_variable == "N" or "n":
                print("You chose no")
                cct.menu_state = "main"
                choosing_another = False
            else:
                choice_variable = input("That was not a valid entry, please enter Y or N only: \n")
                continue
    return


def view():
#TO BE CODED
    return

def decrypt():
    #TO BE CODED
    return

cct.菜单（）

Answer 1

不是python程序员，但我认为python不允许或操作符使用“隐含”主题
&燃气轮机；如果保存选项==“Y”或保存选项==“Y”：

Answer 2

这总是正确的：

if save_choice == "Y" or "y":

因为它被解释为：

if (condition) or (condition):

第一个条件是（save_choice==“Y”）

第二个条件是（“y”），python将其解释为“True”

所以整个情况都是真的

你的意思可能是：

if save_choice == "Y" or save_choice == "y":

或者更好：

if save_choice.lower() == "y":