擅长:python、mysql、java
<blockquote>
<p>In case, you want to sort the same list (in place), you can use "<code>.sort</code>" method on the list.</p>
</blockquote>
<pre><code>list_of_dicts.sort(key= lambda x: x.get('name')[-1]) # key accepts a function, and we are fetching the last letter of the name.
print (list_of_dicts)
</code></pre>
<blockquote>
<p>I hope this helps and counts.</p>
</blockquote>