尝试创建一个函数来验证密码而不使用re或main（），并将返回true或false

Question

def isValidPassword(pw):  
    SpecialSymbol = ["@", "#", "$", " ", "&", "%"]
    val = True   
    
    if len(pw) < 10:
        print("enter at least 10 characters")
        val = False
        
    if not any(char.isdigit(3) for char in pw):
        print("enter at least 3 digit numbers")
        val = False
        
    if not any(char.isupper() for char in pw):
        print("enter at least 1 uppercase letter")
        val = False
        
    if not any(char.islower() for char in pw):
        print("enter at least 1 lowercase letter")
        val = False
        
    if not any(char in SpecialSymbol for char in pw):
        print("enter at least 1 special character")
        val = False
    if val:    
        return val
        
    if (isValidPassword(pw)):
        print(True)    
    else:
        print(False)       
print(isValidPassword("1234rewq"))

它返回[TypeError:str.isdigit（）不接受任何参数（给定1）]，我不知道为什么 抱歉，我刚开始学习，参考了一些我能找到的资料，但我真的不知道我在做什么

Answer 1

在函数isdigit()上使用sum而不是any()

试试这个：

def isValidPassword(pw):  
    SpecialSymbol = ["@", "#", "$", " ", "&", "%"]
    val = True   
    
    if len(pw) < 10:
        print("enter at least 10 characters")
        val = False
        
    if sum(char.isdigit() for char in pw) < 3:
        print("enter at least 3 digit numbers")
        val = False
        
    if not any(char.isupper() for char in pw):
        print("enter at least 1 uppercase letter")
        val = False
        
    if not any(char.islower() for char in pw):
        print("enter at least 1 lowercase letter")
        val = False
        
    if not any(char in SpecialSymbol for char in pw):
        print("enter at least 1 special character")
        val = False
    if val:    
        return val
        
if (isValidPassword("1234rewq")):
    print(True)    
else:
    print(False)