如何将字符串拆分为连续的子字符串，例如：string\u inputs:IN PYTHON3

Question

如何将字符串拆分为连续的子字符串，例如： 字符串\u输入：

AAAATTTT ATATATAT

需要的输出：

AA,AA,AA,AT,TT,TT,TT

Answer 1

string_inputs = "AAAATTTTATATATAT"

#Note the `len(string_inputs) - 1` in the range; do according to what you desire as your output
d_out = [string_inputs[i:i+2] for i in range(0, len(string_inputs) - 1)]

d_out = ['AA', 'AA', 'AA', 'AT', 'TT', 'TT', 'TT', 'TA', 'AT', 'TA', 'AT', 'TA', 'AT', 'TA', 'AT']

Answer 2

您可以在此处使用^{}获得每两个子字符串：

>>> string = 'AAAATTTTATATATAT'
>>> ','.join(x + y for x, y in zip(string, string[1:]))
'AA,AA,AA,AT,TT,TT,TT,TA,AT,TA,AT,TA,AT,TA,AT'

这也是另一种方式：

>>> ','.join(map(''.join, zip(string, string[1:])))
'AA,AA,AA,AT,TT,TT,TT,TA,AT,TA,AT,TA,AT,TA,AT'

甚至像这样：

>>> ','.join(map(lambda x, y: x + y, string, string[1:]))
'AA,AA,AA,AT,TT,TT,TT,TA,AT,TA,AT,TA,AT,TA,AT'

Answer 3

这正是你想要的

string = "AAAATTTTATATATAT"
step = 2
split = [string[i:i+step] for i in range(0, len(string), step)]
print(",".join(split))

step是要将字符串拆分成的块。最后一行将其与,连接起来，如您的示例所示，以提供最终输出AA,AA,TT,TT,AT,AT,AT,AT