输入:
import requests
import json
apikey2 = '1234'
headers = {'API-Key':apikey2,'Content-Type':'application/json'}
data = {"url":urlz2, "visibility": "private"}
r2 = requests.post('https://urlscan.io/api/v1/scan/',headers=headers, data=json.dumps(data))
print(r2)
print(r2.json())
输出:
<Response [200]>
{'message': 'Submission successful', 'uuid': 'xxxxxxxx', 'result': 'https://urlscan.io/result/xxxxxxxxxx/', 'api': 'https://urlscan.io/api/v1/result/xxxxxxxxxxx/', 'visibility': 'private', 'options': {'useragent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_14_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/xxxxxxxx Safari/xxxxxx'}, 'url': 'https://xxxxxxx.io/'}
抓取我想要的信息并在每行打印时遇到问题,如:
message: Submission successful
uuid: xxxxxxxx
result: https://urlscan.io/result/xxxxxxxxxx/
visibility: private
我尝试了一些类似于
for match in r2.json().get('message', []):
print(f'uuid: {message.get("uuid", {}).get("uuid", "Unknown uuid")}')
但是get有一个错误,它是一个字符串
respons.json()
方法返回一个字典。您可以迭代此字典的键和值并打印如果要打印特定键的值,如果找不到该键,则会显示一条消息,可以使用下面的代码。这段代码迭代感兴趣的键,如果该键不在响应字典中,则可以打印消息。否则,打印键和值
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