如何在python中从文本文件生成两个列表？

Question

我想弄清楚如何从一个文本文件中列出两个分开名字和DOB的列表。我在文本文件中看到了如下示例： "Bob Willus, 03/25/1993" 但我的文本文件如下所示：

James B W Bevis
10/12/1943
Henry Bemis
8/4/2008
Romney Wordsworth
8/29/2012

到目前为止，这就是我所拥有的：

file = open("contactsLab4.txt.","r")
names = []
birthdate = []
for line in file:
    splitLine = line.split("\n")
    names.append(splitLine[0])
    birthdate.append(splitLine[0])
print(names)
print(birthdate)

这就是结果：

    ['James B W Bevis', '10/12/1943', 'Henry Bemis', '8/4/2008', 'Romney Wordsworth', '8/29/2012', 
    'Osborne Cox', '1/21/1989', 'Somerset Frisby', '9/5/2010', 'Revis Jacara', '2/16/1935', 'Bartlet 
    Finchley', '11/30/2001', 'Penthor Mul', '5/3/1928', 'Walter Bedeker', '4/27/1996', 'Clegg Forbes', 
    '3/18/2004', 'Jeremy Wickwire', '12/9/1999', 'Luther Dongle', '7/24/1978', 'Klim Dokachin', 
   '10/1/1975', 'Archibald Beechcroft', '6/19/1991', 'Oliver Crangle', '5/6/1954', 'Agnes Grep', 
    '11/4/2013', 'William Feathersmith', '1/11/1967', 'Kalin Tros', '12/28/1955', 'Clovis Bagwell', 
    '7/19/2003', 'Wallace V Whipple', '3/8/1939', 'Jeff Myrtlebank', '8/23/2001', 'Latham Bine', 
    '2/2/1949', 'Jim Pembry', '4/1/1992']
    ['James B W Bevis', '10/12/1943', 'Henry Bemis', '8/4/2008', 'Romney Wordsworth', '8/29/2012', 
    'Osborne Cox', '1/21/1989', 'Somerset Frisby', '9/5/2010', 'Revis Jacara', '2/16/1935', 'Bartlet 
    Finchley', '11/30/2001', 'Penthor Mul', '5/3/1928', 'Walter Bedeker', '4/27/1996', 'Clegg Forbes', 
    '3/18/2004', 'Jeremy Wickwire', '12/9/1999', 'Luther Dongle', '7/24/1978', 'Klim Dokachin', 
    '10/1/1975', 'Archibald Beechcroft', '6/19/1991', 'Oliver Crangle', '5/6/1954', 'Agnes Grep', 
    '11/4/2013', 'William Feathersmith', '1/11/1967', 'Kalin Tros', '12/28/1955', 'Clovis Bagwell', 
    '7/19/2003', 'Wallace V Whipple', '3/8/1939', 'Jeff Myrtlebank', '8/23/2001', 'Latham Bine', 
    '2/2/1949', 'Jim Pembry', '4/1/1992']

请，谢谢

Answer 1

当然，这两种方法都是一样的，因为你没有对它们进行任何区分，你需要确定行中何时包含名称，何时包含日期，有多种方法可以做到这一点，这取决于数据的组织方式或给定行中包含的内容，例如，你可以检查行中的第一个字符是什么，如果它是一个数字，您可以假定它是一个日期，否则您可以假定它是一个名称：

with open("contactsLab4.txt.","r") as file:
    names = []
    birthdate = []
    for line in file:
        line = line.strip() #remove trailing "\n"
        if line[0].isdecimal():
            birthdate.append(line)
        else:
            names.append(line)

    print(names)
    print(birthdate)

Answer 2

我已经用isDigit()函数解决了您的问题：

file = open("contactsLab4.txt","r")
names = []
birthdate = []

for line in file:
    splitedLine = line.split("\n")

    if not (splitedLine[0][0].isdigit()):
        names.append(splitedLine[0])
    else:
        birthdate.append(splitedLine[0])

print(names)
print(birthdate)

file.close()

您提供的输入是：

James B W Bevis
10/12/1943
Henry Bemis
8/4/2008
Romney Wordsworth
8/29/2012

您的输出和我提供的代码将是：

['James B W Bevis', 'Henry Bemis', 'Romney Wordsworth']
['10/12/1943', '8/4/2008', '8/29/2012']

Answer 3

您可以这样做，因为名称和DOB在单独的行中

    names = []
    birthdate = []

    with open("contactsLab4.txt.", "r") as file:
        for index, line in enumerate(file):
            splitLine = line.split("\n")
            if index % 2 == 0:
                names.append(splitLine[0])
            else:
                birthdate.append(splitLine[0])

    print(names)
    print(birthdate)

您可以使用rstrip自动删除换行符