将问题与其各自的选择混在一起

Question

我正在创建一个测验（使用tkinter），我想随机洗牌我将显示的问题，但因为它是多项选择题，我必须确保它被正确的选项洗牌，否则，问题和选项就没有意义了

为了实现这一点，我编写了以下代码：

以下是我的选择：

q1 = ['up','in','out']
q2 = ['off', 'out', 'up']
q3 = ['got', 'get', 'down']
q4 = ['out', 'over', 'up']
q5 = ['up', 'under', 'down']
q6 = ['in', 'on', 'over']
q7 = ['down', 'over', 'up']
q8 = ['in', 'over', 'out']

，以及问题：

questions_list = ['Could you possibly put the rubbish  ___?',
                 'Something\'s cropped ___ at work',
                 'Perhaps we can ___ together then',
                 'He\'s hanging his jacked ___',
                 'She\'s tripped him ___',
                  'He\'s knocked him ___',
                 'He\'s doing his jacked ___',
                 'She\'s put her jumper inside ___']

一旦在列表中定义了它们，我就会在字典中使用它们，如图所示：

choices_dic = {'Could you possibly put the rubbish  ___?': q1,
             'Something\'s cropped ___ at work': q2,
             'Perhaps we can ___ together then': q3,
             'He\'s hanging his jacked ___': q4,
             'She\'s tripped him ___': q5,
              'He\'s knocked him ___': q6,
             'He\'s doing his jacked ___': q7,
             'She\'s put her jumper inside ___': q8}

shuffled = random.sample(questions_list,8) 

我用sample把问题混合起来。为什么？我会添加八个以上的问题，以便在每次重新开始测验时都有不同的问题，或者至少有一些问题是不同的，但现在这并不重要。这就是为什么我在{}中只有八个问题

window = tk.Tk()

因为我已经定义了列表，所以我将label这些问题

num1 = tk.IntVar()
num1.set(4) # I copied this eight times, you'll see why soon.

for i in range(1,9):
questions = tk.Label(window, text = shuffled[i - 1]).grid(column = 0, row = (3*i - 1), columnspan = 3, sticky = tk.W)
for x in range(3):
    options1 = tk.Radiobutton(window, text = choices_dic[str(shuffled[i-1])], variable = num1, value = x)
    options1.grid(column = x, row = 3*i , sticky = tk.W)

    options2 = tk.Radiobutton(window, text = choices_dic[str(shuffled[i-1])], variable = num2, value = x)
    options2.grid(column = x, row = 3*i, sticky = tk.W)

    options3 = tk.Radiobutton(window, text = choices_dic[str(shuffled[i-1])], variable = num3, value = x)
    options3.grid(column = x, row = 3*i, sticky = tk.W)

    options4 = tk.Radiobutton(window, text = choices_dic[str(shuffled[i-1])], variable = num4, value = x)
    options4.grid(column = x, row = 3*i, sticky = tk.W)

    options5 = tk.Radiobutton(window, text = choices_dic[str(shuffled[i-1])], variable = num5, value = x)
    options5.grid(column = x, row = 3*i, sticky = tk.W)

    options6 = tk.Radiobutton(window, text = choices_dic[str(shuffled[i-1])], variable = num6, value = x)
    options6.grid(column = x, row = 3*i, sticky = tk.W)

    options7 = tk.Radiobutton(window, text = choices_dic[str(shuffled[i-1])], variable = num7, value = x)
    options7.grid(column = x, row = 3*i, sticky = tk.W)

    options8 = tk.Radiobutton(window, text = choices_dic[str(shuffled[i-1])], variable = num8, value = x)
    options8.grid(column = x, row = 3*i, sticky = tk.W)

window.mainloop()

这是混乱的，当然是错误的。在我们到达那里之前，我想澄清一下choices_dic[str(shuffled[i-1])]的作用。基本上是按照给定的顺序从choices_dic字典中获取一个元素（检查范围），因为它必须是字符串，所以我使用了str()方法

上面的代码是错误的，因为它执行以下操作：

如您所见，当您选择一个单选按钮时，您将选择其行中的所有单选按钮。您还可以注意到，对于每行中的每个单选按钮，都有一个标记为choices_dic[str(shuffled[i-1])]的列表。不是我想要的

因此，事实上，我还有另一个问题。如何在所有行中显示每个radiobutton的choices_dic中的每个元素，也就是说，不显示每个radiobutton的整个列表三次（如上图所示）

我知道是什么导致了这个问题，但我不知道如何解决它

我希望这足以让你明白我做了什么

编辑： 有一段时间了，我差点忘了我问过这个问题。我的解决办法是： 这很简单。通过上面的步骤，您可以创建一个类或函数来执行代码