请求ssl.ssleofor错误:EOF违反协议(_ssl.c:777)发生

2024-10-01 09:41:44 发布

您现在位置:Python中文网/ 问答频道 /正文

我试图从一个特定的url获取图像数据(参见下面的代码)。他们的安全性已经过时了(见下面的SSL报告),但我还是需要连接到它。我可以用我的浏览器获取图像。在

这就是我要做的:

import requests
url = 'https://www.bestseller.com/webseller/psp.show_picture?picturesId=2367737&thumb=false'
requests.get(url)

我得到的错误是:

^{pr2}$

当我添加参数verify=False时,也会出现相同的错误。在

我已经用pip install requests[security]安装了requests。这是相关的pip freeze输出:

asn1crypto==0.24.0
certifi==2017.11.5
cryptography==2.1.4
ndg-httpsclient==0.4.3
pyasn1==0.4.2
pyOpenSSL==17.5.0
requests==2.8.1
urllib3==1.22

其他配置打印:

>>> import ssl
>>> print(ssl.OPENSSL_VERSION)
OpenSSL 1.0.2n  7 Dec 2017
>>> from cryptography.hazmat.backends.openssl.backend import backend
>>> print(backend.openssl_version_text())
OpenSSL 1.1.0g  2 Nov 2017

有没有一种方法可以禁用设置/验证SSL,或者如果没有,我如何找到需要添加的密码以及如何做到这一点?在

当我尝试编写自己的适配器时:

from requests.adapters import HTTPAdapter
from requests.packages.urllib3.util.ssl_ import create_urllib3_context

# This is the 2.11 Requests cipher string, containing 3DES.
CIPHERS = (
    'ECDH+AESGCM:DH+AESGCM:ECDH+AES256:DH+AES256:ECDH+AES128:DH+AES:ECDH+HIGH:'
    'DH+HIGH:ECDH+3DES:DH+3DES:RSA+AESGCM:RSA+AES:RSA+HIGH:RSA+3DES:!aNULL:'
    '!eNULL:!MD5'
)

class DESAdapter(HTTPAdapter):
    def init_poolmanager(self, *args, **kwargs):
        context = create_urllib3_context(ciphers=CIPHERS)
        kwargs['ssl_context'] = context
        return super(DESAdapter, self).init_poolmanager(*args, **kwargs)

s = requests.Session()
s.mount(url, DESAdapter())

我得到以下错误:

AttributeError: 'super' object has no attribute 'init_poolmanager'

https://www.ssllabs.com/ssltest/analyze.html?d=www.bestseller.com


Tags: fromimportbackendurlssl错误contextrequests
1条回答
网友
1楼 · 发布于 2024-10-01 09:41:44

同时,我使用库pycurl来规避这个问题。在

import urllib.request
from io import BytesIO
from urllib.error import URLError

import pycurl
from django.core.files import File
from django.core.files.base import ContentFile


def _create_attachment_from_url(url: str):
    """
    Fetch the image from the given URL and save it as an attachment
    """

    try:
        file = _fetch_file_using_urllib(url)
    except URLError:
        file = _fetch_file_using_pycurl(url)

    return file


def _fetch_file_using_urllib(url: str) -> (File, str):
    response = urllib.request.urlretrieve(url)
    contents = open(response[0], 'rb')
    file = File(contents)
    return file


def _fetch_file_using_pycurl(url: str) -> (File, str):
    buffer = BytesIO()
    c = pycurl.Curl()
    try:
        c.setopt(c.URL, url)
        c.setopt(c.WRITEDATA, buffer)
        c.perform()
        contents = buffer.getvalue()
        file = ContentFile(contents)
    finally:
        c.close()
    return file

相关问题 更多 >