二和，从内部传递值到函数调用？

Question

我尝试将满足目标的唯一对传递给函数调用。python有点新，所以请告诉我如何修复它

array = [ 3, 4, 5, 9, 10, -1, 6 ]
target = 9
def twoSum (array, target):
    for i in range(0, len(array)):
        for x in range( i + 1, len(array)):
            totalOfTwo = array[i] + array[x]
            if (totalOfTwo == target):
                pairsList = (array[i], array[x])
    return -1
result = twoSum (array, target)

if result != -1:
    print ("the intergers numbers meet target", result)
else:
    print ("result is not in range")

Answer 1

我想这就是你要找的

您需要将这些对添加到列表中，如果找到，则返回它们

另外，就我个人而言，如果没有找到空列表，我会返回空列表，而不是-1，因为它们是不同的数据类型

array = [ 3, 4, 5, 9, 10, -1, 6 ]
target = 9
def twoSum (array, target):
    pairsList = []
    for i in range(0, len(array)):
        for x in range( i + 1, len(array)):
            totalOfTwo = array[i] + array[x]
            if (totalOfTwo == target):
                pairsList.append((array[i], array[x]))
    if len(pairsList) == 0:
        return -1
    else:
        return pairsList
result = twoSum (array, target)

if result != -1:
    print ("the intergers numbers meet target", result)
else:
    print ("result is not in range")