擅长:python、mysql、java
<p>您可以使用zip:</p>
<pre><code>l1 = ([1, 2, 3, 4], ['SHARD', 'METAL_WORK', 'FLINT', 'BONE'], ['BRONZE', 'IRON_AGE', 'MESOLITHIC', 'RECENT'], ['DOMESTIC', 'DECORATIVE', 'HUNTING', 'FOOD'])
result = {k:list(v) for k, v in zip(l1[0], zip(*l1[1:])) }
print(result)
</code></pre>
<p><strong>输出</strong></p>
<pre><code>{1: ['SHARD', 'BRONZE', 'DOMESTIC'],
2: ['METAL_WORK', 'IRON_AGE', 'DECORATIVE'],
3: ['FLINT', 'MESOLITHIC', 'HUNTING'],
4: ['BONE', 'RECENT', 'FOOD']}
</code></pre>