我有一个python列表
['Deals', "\\\\xe2\\\\x98\\\\x85What\\\\\\'s New\\\\xe2\\\\x98\\\\x85", '\\\\xc3\\\\x80la carte & Value Meals', 'Crispy Chicken', 'Share Box', 'Happy Meals', 'Desserts', 'McCafe\\\\xc3\\\\xa9', 'Beverages', 'Side Lines', 'Snack Time']
我想把它像"\\\\xe2\\\\x98\\\\x85What\\\\\\'s New\\\\xe2\\\\x98\\\\x85", '\\\\xc3\\\\x80la carte & Value Meals','McCafe\\\\xc3\\\\xa9'
到'What's New, la carte & Value Meals,McCafe'
一样解码
所需的输出没有任何结束编码(\\x98)
期望输出:
['Deals', "What's New", 'la carte & Value Meals', 'Crispy Chicken', 'Share Box', 'Happy Meals', 'Desserts', 'McCafe', 'Beverages', 'Side Lines', 'Snack Time']
您可以使用内置模块^a1}:
输出:
re.sub(r'x\S\d',' ',s)
将返回字符串s
,其中每3个相邻字符在此模式中:x
,any character that's not a space
,number
替换为一个空格
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