如何在Django中显示图像？

Question

我有一个库存系统。当我点击一种药物时，它会显示这种特定药物的信息。此页面为medicine_details.html。当我打开时，我得到了所有正确的信息，但我看不到图像。在inspect中打开页面时，出现错误：

<img src=(unknown) alt="img">

我怎样才能修好它

视图.py

def medicine_detail(request, id):
    medicine = get_object_or_404(Medicine, id=id)
    context = {
        'medicine': medicine,
    }
    return render(request, 'medicine_details.html', context)

型号.py

class Medicine(models.Model):

    medicine_name = models.CharField(max_length=100)
    medicine_info = RichTextField(verbose_name="notes")
    medicine_code = models.CharField(max_length=100)
    medicine_qr = models.CharField(max_length=100)
    medicine_price = models.IntegerField()
    medicine_stock = models.IntegerField()
    medicine_image = models.ImageField(upload_to='images', null=True, blank=True)
    slug = models.SlugField(max_length=100, unique=True, editable=False)

    def get_image(self):
        if self.medicine_image and hasattr(self.medicine_image, 'url'):
            return self.medicine_image.url
        else:
            return

    def __str__(self):
        return self.medicine_name

    class Meta:
        ordering = ['medicine_name']

    def get_create_url(self):
        return reverse('medicines:medicine_create', kwargs={'slug': self.slug})

    def get_unique_slug(self):
        slug = slugify(self.slug.replace('ı', 'i'))
        unique_slug = slug
        counter = 1
        while Medicine.objects.filter(slug=unique_slug).exists():
            unique_slug = '{}-{}'.format(slug, counter)
            counter += 1
        return unique_slug

    def get_absolute_url(self):
        return reverse('medicines:medicine_create', kwargs={'slug': self.slug})

    def save(self, *args, **kwargs):
        self.slug = self.get_unique_slug()
        return super(Medicine, self).save(*args, **kwargs)

medicine\u details.html

<div class="panel panel-primary">
                <div class="panel-heading text-center"><h3>{{medicine.medicine_name}} </h3></div>
                    <div class="panel-body">


                        <h4><p class="text-success">Medicine Name:  <small>{{medicine.medicine_name}}</small></h4>
                        <h4><p class="text-success">Details:  <small>{{medicine.medicine_info}}</small></h4>
                        <h4><p class="text-success">Barcode:  <small>{{medicine.medicine_code}}</small></h4>
                        <h4><p class="text-success">QR:  <small>{{medicine.medicine_qr}}</small></h4>
                        <h4><p class="text-success">Price:  <small>{{medicine.medicine_price}} TL</small></h4>
                        <h4><p class="text-success"> <small></small></h4>
                        <img src="{{ medicine.medicine_image.url }}" alt="img">

设置.py

MEDIA_ROOT = os.path.join(BASE_DIR, 'media')
MEDIA_URL = '/media/'

url.py ...

url(r'^medicines/(?P<id>\d+)/$', medicine_detail, name="detail"),


    ]
urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

我使用MySQL进行数据库管理

Answer 1

试着这样做：

{% if medicine.medicine_image %}
<img src="{{STATIC_URL}} {{ medicine.medicine_image.url }}" alt="img">
{% endif %}

在设置文件中，您应该具有：

STATIC_URL = '/static/'
STATICFILES_DIRS = [os.path.join(BASE_DIR, 'static')]

如果这不起作用，请张贴您得到的错误

Answer 2

将{{ medicine.medicine_image.url }}替换为

/media/{{ medicine.medicine_image.url }}

Answer 3

在您的设置中，设置：

MEDIA_URL = '/media/'

确保TEMPLATES的context_processors选项中的django.template.context_processors.media

# settings
TEMPLATES = [
    {
        "BACKEND": "django.template.backends.django.DjangoTemplates",
         ...
        "OPTIONS": {
            ...
            "context_processors": [
                ...
                "django.template.context_processors.media",
            ],
        },
    }
]

然后在模板中，您可以使用：

<img src="{{MEDIA_URL}}{{medicine.medicine_image}}" alt="img">

注意：{{MEDIA_URL}}