<p>您可以使用<code>str.split()</code>方法:</p>
<pre><code>from datetime import datetime, timedelta
lst = ['2020-04-02T08:15:50+01:00', '2020-04-02T08:15:53+01:00', '2020-04-02T08:15:56+01:00', '2020-04-02T08:16:01+01:00', '2020-04-02T08:16:07+01:00', '2020-04-02T08:21:05+01:00', '2020-04-02T08:21:17+01:00', '2020-04-02T08:21:30+01:00', '2020-04-02T08:21:43+01:00', '2020-04-02T08:21:49+01:00', '2020-04-02T08:22:11+01:00', '2020-04-02T08:22:16+01:00', '2020-04-02T08:24:02+01:00', '2020-04-02T08:24:09+01:00', '2020-04-02T08:24:37+01:00', '2020-04-02T08:36:26+01:00', '2020-04-02T08:39:25+01:00', '2020-04-02T08:39:41+01:00', '2020-04-02T08:39:52+01:00', '2020-04-02T08:40:18+01:00', '2020-04-02T08:40:27+01:00', '2020-04-02T08:40:33+01:00', '2020-04-02T08:40:49+01:00', '2020-04-02T08:41:03+01:00', '2020-04-02T08:41:29+01:00', '2020-04-02T08:42:00+01:00', '2020-04-02T08:42:23+01:00', '2020-04-02T08:42:57+01:00', '2020-04-02T08:44:43+01:00', '2020-04-02T08:44:49+01:00']
def s(d):
h,m,s = d.split(':',2)
h = int(h[-2:])*60*60
m = int(m)*60
s = int(s[:2])
return h+m+s
c = [1 if s(lst[i-1])-s(d) >= 600 and i else 0 for i,d in enumerate(lst)]
print(c)
</code></pre>
<p>输出:</p>
<pre><code>[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0]
</code></pre>