擅长:python、mysql、java
<p>利用python内置函数和标准库的可能方法。该代码可以与任意数量的键一起使用。在原始目录中出现多个列表的情况下,它会创建值元素的所有组合。不确定此逻辑是否正确</p>
<pre><code>import itertools
def dict_to_inflated_list(d):
ans, keys, vals = list(), list(), list()
# copy keys and 'listified' values in the same order
for k, v in d.items():
keys.append(k)
vals.append(v if isinstance(v, list) else [v])
# iterate over all possible combinations of elements of all 'listified' values
for combination in itertools.product(*vals):
ans.append({k: v for k, v in zip(keys, combination)})
return ans
if __name__ == '__main__':
cond = {'type': 'image', 'questionType': ['3', '4', '5']}
print(dict_to_inflated_list(cond))
cond = {'a': 0, 'b': [1, 2], 'c': [10, 20]}
print(dict_to_inflated_list(cond))
</code></pre>
<p>输出:</p>
<pre><code>[{'type': 'image', 'questionType': '3'}, {'type': 'image', 'questionType': '4'}, {'type': 'image', 'questionType': '5'}]
[{'a': 0, 'b': 1, 'c': 10}, {'a': 0, 'b': 1, 'c': 20}, {'a': 0, 'b': 2, 'c': 10}, {'a': 0, 'b': 2, 'c': 20}]
</code></pre>