用python猜单词

Question

我试图用另外一句话来做一个猜测游戏：你还有“x”个猜测

我基本上写了这些代码：

correctanswer = "Stackoverflow"
useranswer = ""
guesscount= -2
guesslimit = 4
outofguesses = False
while useranswer != correctanswer and not outofguesses == True:
    if guesscount <= guesslimit:
        useranswer = input("Enter your answer : ")
        guesscount += 1
        guesslimit -= 1
        print("Wrong answer , you have " + str(guesslimit) + " guess rights left")
    else: outofguesses = True

if outofguesses:
    print("You lost , sorry")
else:
    print("You won!")

但我无法做到的是，当答案正确时，它仍然会说： （“答错了，你有“+str（猜测限制）+”猜对左边”）然后“你赢了！”

我想做的是，当给出正确答案时，我不希望出现那一行。你能帮我吗

Answer 1

除了使用guesslimit做一些奇怪的事情外，您总是在用户回答之后直接打印“错误答案”，而不执行任何检查以查看是否正确

correctanswer = "Stackoverflow"
guesscount = 0
guesslimit = 3
user_won = False
while guesscount < guesslimit:
    answer = input("Enter your answer : ")
    if answer == correctanswer:
        user_won = True
        break
    else:
        print(f"Wrong answer, you have {guesslimit - guesscount} guesses left")
        guesscount += 1

if user_won:
    print("You won!")
else:
    print("You lost , sorry")

Answer 2

您的打印行在猜测之后和检查是否为真之前处于while循环中，这意味着它仍将执行。 解决这个问题的一种方法是使用一个简单的if语句。您的代码可能看起来像这样 （请注意，guesslimit和guesscount仍将更改，如果您不希望更改，只需将if语句放在更改它们的代码之上）

correctanswer = "Stackoverflow"
useranswer = ""
guesscount= -2
guesslimit = 4
outofguesses = False
while useranswer != correctanswer and not outofguesses == True:
    if guesscount <= guesslimit:
        useranswer = input("Enter your answer : ")
        guesscount += 1
        guesslimit -= 1
        if (useranswer != correctanswer):
            print("Wrong answer , you have " + str(guesslimit) + " guess rights left")
    else: outofguesses = True

if outofguesses:
    print("You lost , sorry")
else:
    print("You won!")