class Date:
def __init__(self, digits): #digits='10/20/21'
self.month = digits[:2] #'10'
self.day = digits[3:5] #'20'
self.year = digits[6:8] #'21'
def __str__(self):
return f"Dated this {self.day} day of {self.month}, 20{self.year}"
def checkday(date): #add 'st', 'nd', 'rd', or 'th' to day
if int(date.day) == 1 or int(date.day) == 21 or int(date.day) == 31:
date.day += 'st'
elif int(date.day) == 2 or int(date.day) == 22:
date.day += 'nd'
elif int(date.day) == 3 or int(date.day) == 23:
date.day += 'rd'
else:
date.day += 'th'
def checkmonth(date): #get name of month
date.month = monthdic[date.month]
months = ['Jan', 'Feb', 'Mar', 'Apr', 'May', 'June', 'Jul', 'Aug', 'Sep', 'Oct','Nov', 'Dec']
monthdic = {str(i): month for i, month in zip(range(1,13), months)}
date = Date(input("Enter date (mm/dd/yy):\t"))
checkday(date)
checkmonth(date)
print(date)
几个错误归结为一个我没有想到的问题:
如果是一月:1/12/14
将不起作用,因为self.month
是1/12/14[:2]
Enter date (mm/dd/yy): 1/12/14
Traceback (most recent call last):
File "date.py", line 38, in <module>
checkday(date)
File "date.py", line 14, in checkday
if int(date.day) == 1 or int(date.day) == 21 or int(date.day) == 31:
ValueError: invalid literal for int() with base 10: '2/'
如果我求助于01/12/14
,这也将不起作用,因为01
是'01'
,并且monthdic['01']
不存在:
Enter date (mm/dd/yy): 01/12/14
Traceback (most recent call last):
File "date.py", line 39, in <module>
checkmonth(date)
File "date.py", line 28, in checkmonth
date.month = monthdic[date.month]
KeyError: '01'
显然
def __init__(self, digits):
self.month = digits[:2]
self.day = digits[3:5]
self.year = digits[6:8]
不是最好的方法,有哪些好的方法(regex除外)
还有一件事:在__init__
内调用checkdate()
和checkmonth
是否合适
最好使用的方法是分割法。您可以拆分正在输入的与
'/'
相关的文本。因此,类似1/12/14
的东西将变成[1, 12, 14]
。剩下的就直截了当了作为@MuhameedJaseemsuggested:
split = digits.split('/')
和split
一起工作。还根据许多人的建议改进了代码。代码现在有点优雅了相关问题 更多 >
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